3x^2-4000x+300000=0

Solution for 3x^2-4000x+300000=0 equation:

3x^2-4000x+300000=0

a = 3; b = -4000; c = +300000;
Δ = b2-4ac
Δ = -40002-4·3·300000
Δ = 12400000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12400000}=\sqrt{40000*310}=\sqrt{40000}*\sqrt{310}=200\sqrt{310}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4000)-200\sqrt{310}}{2*3}=\frac{4000-200\sqrt{310}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4000)+200\sqrt{310}}{2*3}=\frac{4000+200\sqrt{310}}{6}
$